Maths
This query is : Resolved
Querist : Anonymous
Querist :
Anonymous
(Querist)
03 November 2011
The sum of all natural numbers between 100 and 1000 which are multiple of 5 is?
how to calculate?
how to calculate?
04 November 2011
first term is 105
last term is 995
Nth term is 995
so
105+(n-1)5=995
n=179
Sum of 179 terms of AP=179/2(2*105+178*5)
last term is 995
Nth term is 995
so
105+(n-1)5=995
n=179
Sum of 179 terms of AP=179/2(2*105+178*5)
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