How to find value of e ^0.0075 with using log antilog
This query is : Resolved
29 January 2013
in exam ca final how to find value of e ^x .if just logeritham and anti log given. ca final.future. sfm subject
06 February 2013
Let x = e^0.0075
Log x = log e^0.0075
Log x = 0.0075 * log e
Log x = 0.0075 * 0.4343
Log x = 0.0032
x = Antilog 0.0032
x = 1.0075
Log x = log e^0.0075
Log x = 0.0075 * log e
Log x = 0.0075 * 0.4343
Log x = 0.0032
x = Antilog 0.0032
x = 1.0075
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06 February 2013
in sfm,option chapter,black & scholes model. ther is formula of d1 &d2.in d1 formula ,ln(s/k)=ln1.0667=0.06766.so how that come.in module ans that is 0.0645.
My Ques is how to find value and which is right?
My Ques is how to find value and which is right?
06 February 2013
Can you write your query completely?
07 February 2013
ca final sfm there is formula of black scholes model. in formula d1. i am unable to find value of this .natural logaritham (current stock price/strike price of option).
and for example natural logeritham (1.0667) & in book answer given as 0.0645 or 0.0676. how that come.if u find one of above value.
and for example natural logeritham (1.0667) & in book answer given as 0.0645 or 0.0676. how that come.if u find one of above value.
07 February 2013
Natural Logarithm is base "e".
You might be looking at tables for base 10.
The above calculation which I have done is w.r.t base 10.
You might be looking at tables for base 10.
The above calculation which I have done is w.r.t base 10.
07 February 2013
no sir first question is solved by u and it is absolutely true .but i asked another question .that is above given
sir please send ur email id then i will send u scan page then it will help u to solve my query.
mayank11.gohil@gmail.com
sir please send ur email id then i will send u scan page then it will help u to solve my query.
mayank11.gohil@gmail.com
08 February 2013
log (e) 1.0667
= log (10) 1.0667/log (10) e
= 0.028042/0.4343
= 0.064568
Hope it is clear now.
Note - the text in brackets () represents the base.
= log (10) 1.0667/log (10) e
= 0.028042/0.4343
= 0.064568
Hope it is clear now.
Note - the text in brackets () represents the base.
08 February 2013
log of 1.0667 to base 10. I have used MS-excel, you can use logarithm tables to get the answer.
11 February 2013
log of 1.0667. i see 10 in log table 6 position. =0253 comes then add 6th mean diff 25 . it gives values arrond 0278 value & then put dot =0.0278 then it is right . or wrong . bcaz ans r changing .
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