A RIDDLE

This query is : Resolved 

24 October 2008 2 BATSMEN EACH ON 94, 7 RUNS TO WIN IN 3 BALLS ,BOTH MAKE UNBEATEN 100.HOW???THIS QUESTION WAS ASKED IN AN INFOSYS INTERVIEW!! CAN U CRACK IT????

25 October 2008 Ist ball = Ist man put 6 in one ball

OVER !!!!!

IInd Ball =IInd man put 4
IIIRD ball = 2 runs

25 October 2008 Mr.Jitendra, it is not possible as you said, because:

1)when the first man hits six, he continues to bat, second man will not get the second ball.

2)Even if the second man gets a chance and hits a four in the second ball, the match will be over as the required runs are scored and therefore the second man will not get the third ball to complete his 100.


25 October 2008 Guess there is a wide and one run goes to the team ..

25 October 2008 Not a right guess; then how does the batsman complete century?

25 October 2008 1st bALL : ONE BATSMAN HIT A FOUR.

2nd Ball : same batsman make a shot and take three runs but onje run is short and it will be counted as 2 runs.
3rd Ball : the other batsman hit a SIX and won the match.

Both are at unbeaten 100.



Also the case is the overs might be reduced to 48.2 overs or 48.1 overs something then both batsman can hit a SIX

**DM

25 October 2008 But in infosys interview, the answer was like this:
Case 1: A batsman can be given out

1st batsman hits a six....gets caught on d nxt ball...crease
is changed....next batsman hits a six again...

Case 2: No batsman is out

1st batsman hits d ball n hits d keeper'ds helmet kept
behind...he also takes a single...6 runs are added to his
total making it 100...on d next ball ,2nd batsman hits a
six,making his score 100....as simpl as dat....

28 October 2008 Good job ,six out of ten for that




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