maths-exponential
This query is : Resolved
Querist : Anonymous
Querist :
Anonymous
(Querist)
15 December 2009
if 2^a=3^b=12^c then 1/c-1/b-2/a reduces to
16 December 2009
Let 2^a=3^b=12^c = k
i.e.
2= k^1/a or 4 =k^2/a............(i)
3 = k^1/b............(ii)
12 = k^1/c............(iii)
we know that 12/3=4 i.e.
(k^1/c)/(k^1/b )= k^2/a
k^(1/c-1/b) = k^2/a
i.e. 1/a - 1/b = 2/a
i.e. 1/a - 1/b- 2/a= 0
ANSWER is 0 (zero)
i.e.
2= k^1/a or 4 =k^2/a............(i)
3 = k^1/b............(ii)
12 = k^1/c............(iii)
we know that 12/3=4 i.e.
(k^1/c)/(k^1/b )= k^2/a
k^(1/c-1/b) = k^2/a
i.e. 1/a - 1/b = 2/a
i.e. 1/a - 1/b- 2/a= 0
ANSWER is 0 (zero)
You need to be the querist or approved CAclub expert to take part in this query .
Click here to login now
Click here to login now
Similar Resolved Queries
Unanswered Queries
- Invoice Numbers WROGLY ENTERED
- TDS on purchase of value vouchers for employees ?
- PAYMENT TO OPEN AI AND ENVATO ELEMENT
- Issue of gst e invoice
- Interchangeable words in accounts
- Adjusted profit/Loss in the case of LLP and Pvt. Ltd.company
- How to adjusted advances given or receipt
- Foreign vendor without PAN unable to to register due to non receipt of OTP on foreign number ?
- 133(6) DIN INVALID format error - ->WHERE TO REPLY 133(6) notice?
- Query for dubts
Trending Online Classes
-
Excel Mastery Program
CA Rishabh Pugalia
CAclubindia
