maths-exponential


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15 December 2009 if 2^a=3^b=12^c then 1/c-1/b-2/a reduces to

16 December 2009 Let 2^a=3^b=12^c = k
i.e.

2= k^1/a or 4 =k^2/a............(i)

3 = k^1/b............(ii)

12 = k^1/c............(iii)

we know that 12/3=4 i.e.
(k^1/c)/(k^1/b )= k^2/a

k^(1/c-1/b) = k^2/a

i.e. 1/a - 1/b = 2/a

i.e. 1/a - 1/b- 2/a= 0

ANSWER is 0 (zero)


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