Fm queries

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Shalini (Querist)
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20 January 2014 can any1 explain me hw to find value of ln 1.0375. ans is 0.036814.. and ln 1.066 0.0647.. I m nt geting hw to find this values...

P V Ram

P V Ram (Expert)
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20 January 2014 ln of 1.03 is .029559 & ln of 1.04 is .039221 from natural log tables.

Interpolating the above values for 1.0375 we get .0368055.

Similarly ln 1.066 can be found through ln1.06 & ln1.07

In case of .0647 we can find the value by writing .0647 as (6.47 / 10*10)i.e. ln.0647 = ln6.47-ln10-ln10.

We can find the value from Excel or natural log calculators also.

I hope you would be able to do it now. If not, please let me know.

Thanks!