24 October 2008
2 BATSMEN EACH ON 94, 7 RUNS TO WIN IN 3 BALLS ,BOTH MAKE UNBEATEN 100.HOW???THIS QUESTION WAS ASKED IN AN INFOSYS INTERVIEW!! CAN U CRACK IT????
25 October 2008
In the first ball the first man scores 6 off the first ball to reach 100.
In the second ball the batsmen cross on the pretext of a leg-bye but disallowed by umpire as deliberate padding. But as the batsmen cross the second man gets to batting
Second man hits a six in the third ball to reach 100.
25 October 2008
First batsman hits a six, makes 100. 1 run to win. Next ball he gets hit on the pad not offering a shot, they run but it is not counted as a run because it is a dead ball. Second batsmen hits a six next ball to make 100. First player hits 6,goes to 100. Next ball batsmen run on a bye, 2nd batsmen now on strike hits 6 and moves to 100. both now on 100 from the 3balls, bye is recorded as EXTRAS . First of all let me compliment you for this good intelligent quiz question. The first batsman hits the first of the three balls behind the wicket keeper, the hit touches the helmet placed behind the wicket keeper for which he gets five runs; the next ball he takes a single and he completes his hundred. Of the third and last ball the other batsman hits a six and he also completes his hundred. I don't think this is possible, with both batsmen getting their 100s unbeaten. First of all, the answers already given are good but there seems to be something wrong with each. If a batsman gets 6 and then a bye...thats the end of the game, hows is the second batsman going to get his 100?
Secondly, if the ball hits the helmet, the teams gets those 5 runs as extras, not the batsman.
Thirdly, if batsmen run on a dead ball, these runs arn't counted and the batsmen can't change strike as far I know.
The only way I can think of is that the 1st batsman hits a 6. Then on the 2nd ball, he hits it in the air and gets caught AFTER the batsmen have crossed. Thus the 1st player is out and the 2nd batsman is on strike and gets a 6 off the last ball. However, you wanted them to be unbeaten...so it can't be done! someone asked this before. and once again I will say its not possible. 1) byes and leg byes will still reduce the number of runs required to win. 2) helmet hits are counted as extras as someone just said. 3) the problem lies is the fact that its 7 runs. The first batsmen hits a 6 off the 1st ball, pulls a muscle and goes off injured. The new batsmen hits the 2nd ball in the air and is caught while the 2 batsmen cross. The 2nd batsmen on 94 hits the last ball for 6. They both have unbeaten 100s. both of the batsmen hit 6s on their next ball.
CAclubindia
