Share your(questions) doubts - CPT exam

Originally posted by : Gaurav Mohnani
	integrate (2^3x).(3^2x).(5^x) dx  PLEASE ISKA ANSWE BATA DO IS IT (2^3x).(3^2x).(5^x) / log(180) ?

log 360

Immovable property wale me Implied nahi ayega... purchasing Immoveable assets e.g. Land, Building etc. is not under Implied authority.. I marked Restricted :-p, but I think its Express only..

Try this one CPT Dec 2012

Originally posted by : Aditya
	Immovable property wale me Implied nahi ayega... purchasing Immoveable assets e.g. Land, Building etc. is not under Implied authority.. I marked Restricted :-p, but I think its Express only..

 its Express only..

Originally posted by : Aditya
	Try this one CPT Dec 2012

in it most of the answers are wrong.........

Originally posted by : Aditya
	Originally posted by : harish ragav Originally posted by : Aditya my answer to the probability question was wrong.. sorry which question?   multiple of 2 & 3 wala!

yes the ans is none of the above i  think.........

 

Originally posted by : Aditya
	Try this one CPT Dec 2012

isme kitne alag ans h :((((((((((((

Originally posted by : PARUL
	Originally posted by : Aditya Try this one CPT Dec 2012 isme kitne alag ans h :((((((((((((

pls post ur doubts and ans in english .........

@ ADITYA HOW IT CAN BE LOG(360) ? @ PARUL The question might be the number of classes because, the length of the class and class interval are one and the same. If so, The first class should include the smallest item (44) and the last class should include the largest item (73) One of the principles of classification is that the first class/lower limit of a class should start with 0 or a multiple of 5 Therefore, considering the above and assuming the length of the class as 5, the classes will be 40-45, 45-50, 50-55, 55-60, 60-65, 65-70, 70-75 Number of classes = 7

@ Gaurav - I mean 2^3x 3^2x 5^x/log 360

Int. of a^x = a^x/log a

2^3x 3^2x 5^x

= Int. 8^x 9^x 5^x

=Int. 360^x

=360^x /log 360 or 2^3x 3^2x 5^x/log 360

@ Aditya, Can't we just solve lyk this

 

integrate (2^3x)(3^2x)(5^x) 

step 1:  { 2^3x/log(2).3 } { 3^2x/log(3).2 } { 5^x/log(5) }

step 2:  (2^3x)(3^2x)(5^x)/log(180) + c

@ Aditya, Can't we just solve lyk this

 

integrate (2^3x)(3^2x)(5^x) 

step 1:  { 2^3x/log(2).3 } { 3^2x/log(3).2 } { 5^x/log(5) }

step 2:  (2^3x)(3^2x)(5^x)/log(180) + c

Originally posted by : Gaurav Mohnani
	@ Aditya, Can't we just solve lyk this   integrate (2^3x)(3^2x)(5^x)  step 1:  { 2^3x/log(2).3 } { 3^2x/log(3).2 } { 5^x/log(5) } step 2:  (2^3x)(3^2x)(5^x)/log(180) + c

you've applied the formula correctly, but method is wrong :)

and one thing

(loga + logb + logc) = (log abc), but
(loga. logb. logc) is not equal to (log abc)

my method is correct, how can you make 2^3x=8^x as 3x is in power, u cannot cube 2.