intermediate(ipc)course (no) (1460 Points)
10 September 20111).if f(x) = x+1,.g(x) = x^2+1 fog (-2) =?
ans: 6.
2).if f(x-1) = x^2-4x+8 then f(x+1) = ?
ans : x^2+4
3).the value of 2logx+2logx^2+2logx^3 -----------------------nlogx^n =
ans: n(n+1)logx.
4).the recurring decimal 2.777 -----------is expressed as
ans: 25/9.
5).one root of x^2-3x+k = 0 is 2 then k is
ans: 2.
6).the value of k for which the roots of the equation 12x^2+kx+5 = 0 in the ratio 3:2.
ans: 5.10^1/2.
Prakash
(Chartered Accountant)
(560 Points)
Replied 10 September 2011
Finally What do you want to Express Mam !!
Could't find anything to solve !!
rohit
(CA FINAL)
(41 Points)
Replied 10 September 2011
isse kahte h attempt ka pressure "kya question hai...... lagta hi nahi ki question h.... 
Ankit Hinduja
(Student)
(1227 Points)
Replied 11 September 2011
for 1.f(x)=x+1,g(x)=x^2+1
so, f(g(x))=f(x^2+1)
=x^2+1+1
=x^2+2
now,f(-2)=(-2)^2+2(substituting x= -2 )
=4+2=6
Ankit Hinduja
(Student)
(1227 Points)
Replied 11 September 2011
for2.
2logx + 2log x^2 + 2logx^3+..........+nlogx^n
=2logx + 2.2logx + 2.3logx+.......+n.nlogx(by formula logx^n=nlogx)
=2logx(1+2+3+.....+n) ( taking out 2logx as common)
=2logx.n(n+1)/2 ( 1+2+3+....+n=n(n+1)/2)
=n(n+1)logx
if u r facing problem in maths u can refer maths books of 11th and 12th science group of any of ur science group friends .it will surely help..
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