I have three jug whose capacity are 8 lt.,5 lt. and 3 lt. and no one jug is calibrated then how can I divide 8 lt. water in two equal parts.
CA CS CIMA Prakash Somani (Landmark Group) (23502 Points)
19 June 2008I have three jug whose capacity are 8 lt.,5 lt. and 3 lt. and no one jug is calibrated then how can I divide 8 lt. water in two equal parts.
CA CS CIMA Prakash Somani
(Landmark Group)
(23502 Points)
Replied 20 June 2008
Its simple yaar..just try.
If you need a hint than tell me...
Rushikesh
(Chartered Accountant - Manager Finance)
(2375 Points)
Replied 20 June 2008
Need a hint!!!
nilesh dube
(Service )
(74 Points)
Replied 20 June 2008
the procedure to divide the water equally is
Jug 8 5 3
Water - 5 3
3 5 -
3 2 3
6 2 -
6 - 2
1 5 2
1 4 3
4 4
CA CS CIMA Prakash Somani
(Landmark Group)
(23502 Points)
Replied 20 June 2008
Excellent affords..you can make it simple.
Rishubh Mathur
(Analyst -Taxation)
(442 Points)
Replied 20 June 2008
Jug 8 L 5 L 3 L
Steps
01 8 0 0
02 3 5 0
03 3 2 3
04 6 2 0
05 6 0 2
06 1 5 2
07 1 4 3
08 4 4 0
CA CS CIMA Prakash Somani
(Landmark Group)
(23502 Points)
Replied 20 June 2008
good job...Now try for Chess board? you wil find it Interesting.
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