1).given observations 4,9,11,14,37 mean deviation about median is
a).11, b).8.5, c).7, d).4.75.
2).if X ~ n(3,36) & Y~ N(5,64) then X + Y ~ (8,A).the value of A is
a)100, b).10, c).64, d).36.
intermediate(ipc)course (no) (1460 Points)
26 October 20111).given observations 4,9,11,14,37 mean deviation about median is
a).11, b).8.5, c).7, d).4.75.
2).if X ~ n(3,36) & Y~ N(5,64) then X + Y ~ (8,A).the value of A is
a)100, b).10, c).64, d).36.
CA VISHAL RANA,CS,B.Com,AMFI
(Chartered Accountant in Whole Time Practice)
(4354 Points)
Replied 26 October 2011
Q1 ANS- A,11
Q2 ANS- A,100
intermediate(ipc)course
(no)
(1460 Points)
Replied 26 October 2011
clarify the answer please........................................
CA VISHAL RANA,CS,B.Com,AMFI
(Chartered Accountant in Whole Time Practice)
(4354 Points)
Replied 26 October 2011
QNO-1= MEDIAN=(N+1)/2TH TERM IS MEDIAN=(5+1)/2=3RD TERM IS MEDIAN,WHICH IS 11. ans
QNO-2=X+Y THEN ALLVARIABLE WILL BE IN SUM=E.G 3+5=8 AS IT IS 36+64=100 ans
intermediate(ipc)course
(no)
(1460 Points)
Replied 26 October 2011
2nd question i can't understand..
CA VISHAL RANA,CS,B.Com,AMFI
(Chartered Accountant in Whole Time Practice)
(4354 Points)
Replied 26 October 2011
VARIABLES OF X= (3,36)
VARIABLES OF Y = (5,64)
X+Y=SUM OF VARIABLES
X+Y=3+5 & 36+64=(8,100)
100 IS VALUE OF A
intermediate(ipc)course
(no)
(1460 Points)
Replied 26 October 2011
ok 2nd question i understand but 1st question is mean deviation about median.
CA Mohit Mohan
(c.a. profession)
(557 Points)
Replied 26 October 2011
is answe for first ques is 7.6 exactly
CA Mohit Mohan
(c.a. profession)
(557 Points)
Replied 26 October 2011
median is 11
4-11= 7 ( ignoring -ve sign)
9-11=2
11-11 =0
14-11=3
37-11 = 26
now take simple average of (7+2+0+3+26)/5 = 7.6
tell ... is answer ryt