Go AD-Free with CAclubindia Pro and Daily WhatsApp Updates. Subscribe Now!

sets & relations

7760 views

Save Share

Join Us Follow Us Add as Source

mridul savio Pinto

articled trainee

769 Points Posted on 18 January 2011

can any one help me to solve this

out of 2000 employees in an office 48 % like cofee 54 % like tea and 64 % like smoke , out of total 28 % used c and t , 32 % used t and s 30 % preferred c and s only 6 % did none of these . the number having all the three is ?

a. referred to question no of employees using t and s but not c?

b . no of employees prefer only coffee ?

Replies (4)

Rahul Agarwal

N.A.

91 Points Posted on 18 January 2011

P(C)=48%
P(T)=54%
P(S)=64%
P(C&T)=28%
P(T&S)=32%
P(C&S)=30%
P(NONE)=6%

To find the number of people who do all:
100-(48+54+64-28-32-30+6)=18
Therefore 18% have all three.

a) Using T & S but not C:
32+28+30-48=42
Therefore 42% use T & S but not C.

b) only coffee:
48+28+32+30-54-64=20
Therefore 20% prefer only coffee.

If you understood and were helped, "thank user"

CA NISHANT SAURABH

442 Points Posted on 18 January 2011

Originally posted by : Rahul Agarwal
	P(C)=48% P(T)=54% P(S)=64% P(C&T)=28% P(T&S)=32% P(C&S)=30% P(NONE)=6% To find the number of people who do all: 100-(48+54+64-28-32-30+6)=18 Therefore 18% have all three. a) Using T & S but not C: 32+28+30-48=42 Therefore 42% use T & S but not C. b) only coffee: 48+28+32+30-54-64=20 Therefore 20% prefer only coffee. If you understood and were helped, "thank user"