Permutations and combinations

928 views 2 replies

I have 2 questions

1) A question paper contains 6 questions,each havinbg an alternative.The number of ways and examinee can answer one

or more questions is

a)720  b)728  c)729  d)None of these

 

2)The number of ways in which 12 students can be equally divided into 3 groups is

a)5775  b)7575  c)7755 d)none of these

 

Thanks in advance

Replies (2)

1. the number of options for each question is 3( not answering, first alternative,second alternative) and all questions have same options. so the total no. of options is 3*3*3*3*3*3 = 3^6 = 729 but this also contains the option no answers answered. henbce 728

for the second question /forum/maths-plz-solve-198734.asp#.T9NJ1LEtjsQ follow this link the answer is given in that the answer is 5775

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