Chartered Accountant
334 Points
Joined April 2009
If a, b and c are in Arithmetic Series, then 1/a, 1/b, 1/c are in Harmonic series.
So, if b is the Arithemetic mean of a and c. 1/b is the Harmonic Mean of 1/a and 1/c
Mathematical Derivation:
For easiness, lets say x, y, z are in HM i.e. x = 1/a, y = 1/b, and z=1/c
Now, using the formula of AM, we get b = (a+c)/2.
Now, Harmonic Mean = 1/b = 2/(a+c)
Converting Values in x, y, and Z. We get. HM = y = 2/(1/x+1/z)
= 2/((x+z)/xz)
= 2*xz/(x+z)
= 2xz/(x+z)
Above is the derivation for harmonic Mean of two numbers x and z.
USAGE:
Some things exhibit harmonic properties like velocity.
Example. If we travel a certain distance of 100 km from A to B, at 20 Km/hr and then B to A at 50 Km/hr, then what is the average velocity.
Solution: Since velocity exhibit Harmonic Properties, Average Velocity is HM between them,
Therefore, Average Velocity = 2*50*20/(50+20)
= 200/7 km/hr
If we calculate direct average i.e. AM, it will be wrong. Here AM of 50 & 20 will be 35 km/hr.
Cross Check:
Total Time taken from A to B = 100/20 = 5 Hr
Total time taken from B to A = 100/5 = 2 Hr
Total time taken for return journey = 2 Hr+5 Hr = 7 Hr
Total Distance for Return Journey = 100+100 = 200 km
So, Average Velocity = 200/7 km/hr