average age of a group of 10 students is 20 years,if average age increased by two years when two new students are joined then the average age of two new students
a).84 b).64
c).32 d).42
19 Replies
Dhairya
(Audit-in-charge)
(289 Points)
Replied 16 March 2012
.32 i guess
What's the correct answer by the way?
intermediate(ipc)course
(no)
(1460 Points)
Replied 16 March 2012
kindly doing my sum immediately....
Sanket
(!..Live to Give..!)
(16427 Points)
Replied 16 March 2012
See total Age of 10 Students = 10 Students * 20 Years = 200
New Average = 20 Years + 2 Years = 22 Years
Total Age of 12 Students = 12(10+2) Students * 22 Years = 264
Total age of the 2 new students = 264 - 200 = 64
Avg age of the new students = 64 / 2 = 32 years
intermediate(ipc)course
(no)
(1460 Points)
Replied 16 March 2012
if x is inversely related with square of y for x =1 & y=2 then find the value of x when y=6 :
a).3 b).9
c).1/3 d).1/9
Ankit
(CA Final)
(75 Points)
Replied 16 March 2012
X = 9
as x = 1/y2 and the retio of x : y comes out to be 1 : 1/4 i.e 4 : 1
if we put y = 6, then x = 1/36 and ratio is 4: 1
from where x comes out to be 9.
deepak
(Chartered Accountant Company Secretary)
(94 Points)
Replied 16 March 2012
C) Thirty Two 32 !!
Neha Dhapola
(Student)
(305 Points)
Replied 17 March 2012
The answer of your first question is c.) 32
And of other is b.) 9
Manjul Soni.
(CA Student.)
(1407 Points)
Replied 17 March 2012
| Originally posted by : !..SaNKeT..! | ||
 |
See total Age of 10 Students = 10 Students * 20 Years = 200 New Average = 20 Years + 2 Years = 22 Years Total Age of 12 Students = 12(10+2) Students * 22 Years = 264 Total age of the 2 new students = 264 - 200 = 64 Avg age of the new students = 64 / 2 = 32 years |
 |
intermediate(ipc)course
(no)
(1460 Points)
Replied 17 March 2012
if p & q are roots of x^2-bx+c=0then the equation whose roots are (pq+p+q) & (pq-p-q) is :
a).x^2-2cx+c^2-b^2=0
b).x^2-2bx+c^2+b^2=0
c).cx^2-2(b+c)x+c^2=0
d).x^2+2bx-(c^2-b^2)=0
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