sir please give answer to these doubts
1.Rtp 2015 qustion no 7 in answer how we getting the depreciation amount 64000
2.formula for effective cost of factoring and effective rate of interest of factoring the firm
ramesh pai (student) (59 Points)
22 October 2015sir please give answer to these doubts
1.Rtp 2015 qustion no 7 in answer how we getting the depreciation amount 64000
2.formula for effective cost of factoring and effective rate of interest of factoring the firm
Rohit Singh
(student)
(48 Points)
Replied 22 October 2015
600000-200000-(600000*0.04*14)= 64000
cost of machine = 600000
1st year depn = 200000
next 14 years depn = 600000*0.04*14
hope that helps
ramesh pai
(student)
(59 Points)
Replied 22 October 2015
please make more clear.
600000*4%*14 came to 336000
Rohit Singh
(student)
(48 Points)
Replied 22 October 2015
336000 is depreciation for 14 years
cost - depreciation = scrap value
600000-200000-336000= 64000
ramesh pai
(student)
(59 Points)
Replied 23 October 2015
thank you for kind information.please provide answer for second part