Cpt - qa qstn ... plz help

906 views 2 replies

given that:

log 2 X  (ie log x to the base 2) + log 4 X  +log 16 X = 21/4 then x =??

answr as per icai module is 8 bt i dont know how to solve...

Replies (2)

 

You know the formula, Log an pm= m/n logap

Applying the formula,

Log2x + 1/2 Log2x + 1/4 Log2x = 21/4

Taking Log2x common,

(1 + 1/2 + 1/4) Log2x = 21/4

(7/4) Log2x = 21/4

Log2x = 3

X =23 = 8

 

 Applying the formula,

Log2x + 1/2 Log2x + 1/4

Log2x = 21/4

Taking Log2x common, (1 + 1/2 + 1/4) Log2x = 21/4 (7/4)

Log2x = 21/4

Log2x = 3 X =23 = 8

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