Commerce Coaching- Accounts Cost FM
735 Points
Joined January 2008
the prob can be solved by apllying maxima minima.
Let 'y' be the total contribution that has to be maximised and 'x' be the selling price . now set the following equation:
y= [10000-(x-25)X500/0.5](x-17)
y=52000x-595000-1000x2
then dy/dx=52000-2000x and d2y/dx2=-2000
setting dy/dx=0 we get 52000-2000x=0 or x=26 hence the selling price is Rs.26. the quantity sold is 9000units.