1) If 2+3=10 , 6+5=66 , 7+2 =63 , 9+6= (?)
2) 0 , 2 , 36 , 80 , 150 , ___ , 392
8 Replies
CA Mani
(Credit Analyst)
(2814 Points)
Replied 20 November 2009
First one is 135 second one is i am thinking
CA Raj Patel
(Practicing CA @ Ahmedabad)
(90 Points)
Replied 20 November 2009
Sorry dude, I've made mistake. I have missed 12 in series. revised on is below
0 , 2 , 12 , 36 , 80 , 150 , ___ , 392
Very sorry......
CA Raj Patel
(Practicing CA @ Ahmedabad)
(90 Points)
Replied 20 November 2009
yes.. you are absolutely right....
Sudhit
(no)
(248 Points)
Replied 20 November 2009
ya 1st one is 135
2nd is tough one.....i m also thinking
CA Mani
(Credit Analyst)
(2814 Points)
Replied 20 November 2009
| Originally posted by :Raj Patel | ||
| " | Sorry dude, I've made mistake. I have missed 12 in series. revised on is below 0 , 2 , 12 , 36 , 80 , 150 , ___ , 392 Very sorry...... |
" |
yaar iski wajah se socho kitna tough ho gaya mere liye maine socha 2 cube + 2 square = 2 kaise ho gaya........... HA HA
sumit
(Industrial Trainee at EY)
(366 Points)
Replied 20 November 2009
| Originally posted by :Raj Patel | ||
| " | 1) If 2+3=10 , 6+5=66 , 7+2 =63 , 9+6= (?) 2) 0 , 2 , 36 , 80 , 150 , ___ , 392 |
" |
1) answer is 135
i.e 2+3*2 6+5*6
2)ans is 252 only
formula n^2+n^3
i.e in oth place 0^2+0^3=0
1st place 1^2+1^3=2
2nd place 2^2+2^3=12 and so on
sumit
(Industrial Trainee at EY)
(366 Points)
Replied 20 November 2009
now solve this
1,11,21,1211,111221,????.
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