A real test to your maths aptitude!!! try it out!!!

If

*Jon can do a piece of work in 10 days,

*Sam can do it in 15 days and

*Pip can do it in 30 days,

 

how many days will it take if all the three of them work together to complete it?

 

Note: Assume average rates!!!

Replies (14)

in 5 days . is it right?????

 

  5 days

days                     10                  15                   30 

km/day                30                   20                    10

total km             300                   300                   300

Total km of all three 30+20+10=60

Total km needs to cover 300

Days required  300/60= 5 

 

Its 5 days, u are very correct harshita

plz explian the logic of 5days??

 

 

 (10 -.99) = 9days

Takin Jon as the base..10 days are minimum reqd to complete the work...so Johns efficiency is 100%,
sam efficiency is 10/15*100=66.67%
Pip efficiency= 10/30*=33.33%
 

so if they all work together..average efficiency of each person = (100+66.67+33.33)/3=66.67%

So therefore if they all work together they wud require 15 days to complete on average by 1 person....so if they all work together,,,,

its 15/3=5 days.

J work in 1 day 1/10

S work in 1 day 1/15

P work in 1 day 1/30

All works in 1 day 1/10+1/15+1/30=6/30=1/5

All complete the work in 5 days

Jon  alone can complete it in 10 days.

Then how can it be above 10 if they work altogether !

jon completes the work in one day 1/10
Sam completes the work in one day 1/15
Pip completes thew work in one day 1/30
If all work together in one day they will complete 1/10+1/15+1/30 = 1/5
If they complete 1/5 of work in one fay working together they can complete the work in 5 days

Originally posted by : Md. Rafi

J work in 1 day 1/10

S work in 1 day 1/15

P work in 1 day 1/30

All works in 1 day 1/10+1/15+1/30=6/30=1/5

All complete the work in 5 days

Perfect!

 

Try this (a tricky question):

/forum/a-very-tricky-question-very-short-one--231062.asp#.UMm4YOQ3vpw

Originally posted by : raunak

Takin Jon as the base..10 days are minimum reqd to complete the work...so Johns efficiency is 100%,
sam efficiency is 10/15*100=66.67%
Pip efficiency= 10/30*=33.33%
 

so if they all work together..average efficiency of each person = (100+66.67+33.33)/3=66.67%

So therefore if they all work together they wud require 15 days to complete on average by 1 person....so if they all work together,,,,

its 15/3=5 days.

 

Dear Raunak,

 

I didn't get you! I guess its pretty complicated!

So could you please elucidate your working!

These kinds of Questions were asked in 8th Standard.

:D

Answer is 5

Everyone here knows that

its 5 days ...

Its similar to mohd rafis' solution....just dat he calculated work done by each person in 1 day.....and i calculated each persons efficiency,.

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